Solve {l}{x=2}{y=-4}{z=(x-y)^3}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = 2 }\\ { y = -4 }\\ { z = {(x - y)} ^ {3} }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=216$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=\left(2-\left(-4\right)\right)^{3}$$

Multiply -1 and -4 to get 4.

$$z=\left(2+4\right)^{3}$$

Add 2 and 4 to get 6.

$$z=6^{3}$$

Calculate 6 to the power of 3 and get 216.

$$z=216$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=216$$

The system is now solved.

$$x=2 y=-4 z=216 a=216$$