Solve {l}{x=2}{y=-2}{z=3xy^4}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = 2 }\\ { y = -2 }\\ { z = 3 x y ^ {4} }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=96$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=3\times 2\left(-2\right)^{4}$$

Multiply 3 and 2 to get 6.

$$z=6\left(-2\right)^{4}$$

Calculate -2 to the power of 4 and get 16.

$$z=6\times 16$$

Multiply 6 and 16 to get 96.

$$z=96$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=96$$

The system is now solved.

$$x=2 y=-2 z=96 a=96$$