Solve for x, y, z
z=\frac{1}{32}=0.03125
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y=2^{-5}
Consider the second equation. Insert the known values of variables into the equation.
y=\frac{1}{32}
Calculate 2 to the power of -5 and get \frac{1}{32}.
z=\frac{1}{32}
Consider the third equation. Insert the known values of variables into the equation.
x=2 y=\frac{1}{32} z=\frac{1}{32}
The system is now solved.
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