Solve {l}{x=12}{y={(9x^2+24x+16)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = 12 }\\ { y = {(9 x ^ {2} + 24 x + 16)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=1600$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=9\times 12^{2}+24\times 12+16$$

Calculate 12 to the power of 2 and get 144.

$$y=9\times 144+24\times 12+16$$

Multiply 9 and 144 to get 1296.

$$y=1296+24\times 12+16$$

Multiply 24 and 12 to get 288.

$$y=1296+288+16$$

Add 1296 and 288 to get 1584.

$$y=1584+16$$

Add 1584 and 16 to get 1600.

$$y=1600$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1600$$

The system is now solved.

$$x=12 y=1600 z=1600$$