Solve {l}{x=1}{y=8x+32}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { x = 1 }\\ { y = 8 x + 32 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=40$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=8\times 1+32$$

Multiply 8 and 1 to get 8.

$$y=8+32$$

Add 8 and 32 to get 40.

$$y=40$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=40$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=40$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=40$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=40$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=40$$

The system is now solved.

$$x=1 y=40 z=40 a=40 b=40 c=40 d=40$$