Solve {l}{x=1}{y=-56}{z={(8x+6)}{(8x+6)}}{text{Solvefor}a,btext{where}}{a=y}{b=z}

$$\left. \begin{array} { l } { x = 1 }\\ { y = -56 }\\ { z = {(8 x + 6)} {(8 x + 6)} }\\ { \text{Solve for } a,b \text{ where} } \\ { a = y }\\ { b = z } \end{array} \right.$$

Solve for x, y, z, a, b

$$a=-56$$

$$b=196$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=\left(8\times 1+6\right)\left(8\times 1+6\right)$$

Multiply 8\times 1+6 and 8\times 1+6 to get \left(8\times 1+6\right)^{2}.

$$z=\left(8\times 1+6\right)^{2}$$

Multiply 8 and 1 to get 8.

$$z=\left(8+6\right)^{2}$$

Add 8 and 6 to get 14.

$$z=14^{2}$$

Calculate 14 to the power of 2 and get 196.

$$z=196$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=196$$

The system is now solved.

$$x=1 y=-56 z=196 a=-56 b=196$$