Solve {l}{x=1+3}{y=x/6}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = 1 + 3 }\\ { y = \frac{x}{6} }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=\frac{2}{3}\approx 0.666666667$$

Solution Steps

Consider the first equation. Add 1 and 3 to get 4.

$$x=4$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{4}{6}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$y=\frac{2}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{2}{3}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=\frac{2}{3}$$

The system is now solved.

$$x=4 y=\frac{2}{3} z=\frac{2}{3} a=\frac{2}{3}$$