Solve {l}{x=-5}{y=-3}{z={(-3-2x)}{(-y-3)}}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { x = -5 }\\ { y = -3 }\\ { z = {(-3 - 2 x)} {(-y - 3)} }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=0$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=\left(-3-2\left(-5\right)\right)\left(-\left(-3\right)-3\right)$$

Multiply -2 and -5 to get 10.

$$z=\left(-3+10\right)\left(-\left(-3\right)-3\right)$$

Add -3 and 10 to get 7.

$$z=7\left(-\left(-3\right)-3\right)$$

The opposite of -3 is 3.

$$z=7\left(3-3\right)$$

Subtract 3 from 3 to get 0.

$$z=7\times 0$$

Multiply 7 and 0 to get 0.

$$z=0$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=0$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=0$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=0$$

The system is now solved.

$$x=-5 y=-3 z=0 a=0 b=0 c=0 d=0$$