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Solve for x, y, z
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y=6\times \left(3\left(-5\right)\right)^{2}
Consider the second equation. Insert the known values of variables into the equation.
y=6\left(-15\right)^{2}
Multiply 3 and -5 to get -15.
y=6\times 225
Calculate -15 to the power of 2 and get 225.
y=1350
Multiply 6 and 225 to get 1350.
z=1350
Consider the third equation. Insert the known values of variables into the equation.
x=-5 y=1350 z=1350
The system is now solved.