Solve {l}{x=-2}{y={(3-x)}{(3+4)}}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { x = -2 }\\ { y = {(3 - x)} {(3 + 4)} }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=35$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(3-\left(-2\right)\right)\left(3+4\right)$$

Multiply -1 and -2 to get 2.

$$y=\left(3+2\right)\left(3+4\right)$$

Add 3 and 2 to get 5.

$$y=5\left(3+4\right)$$

Add 3 and 4 to get 7.

$$y=5\times 7$$

Multiply 5 and 7 to get 35.

$$y=35$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=35$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=35$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=35$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=35$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=35$$

The system is now solved.

$$x=-2 y=35 z=35 a=35 b=35 c=35 d=35$$