Solve {l}{x=-2}{y=2+5x-x^2}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = -2 }\\ { y = 2 + 5 x - x ^ {2} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-12$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=2+5\left(-2\right)-\left(-2\right)^{2}$$

Multiply 5 and -2 to get -10.

$$y=2-10-\left(-2\right)^{2}$$

Subtract 10 from 2 to get -8.

$$y=-8-\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$y=-8-4$$

Subtract 4 from -8 to get -12.

$$y=-12$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-12$$

The system is now solved.

$$x=-2 y=-12 z=-12$$