Solve {l}{x=-2}{y={(3-x)}{(3+4)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = -2 }\\ { y = {(3 - x)} {(3 + 4)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=35$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(3-\left(-2\right)\right)\left(3+4\right)$$

Multiply -1 and -2 to get 2.

$$y=\left(3+2\right)\left(3+4\right)$$

Add 3 and 2 to get 5.

$$y=5\left(3+4\right)$$

Add 3 and 4 to get 7.

$$y=5\times 7$$

Multiply 5 and 7 to get 35.

$$y=35$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=35$$

The system is now solved.

$$x=-2 y=35 z=35$$