Solve {l}{x=-1}{y={(63/x)}-2^4}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { x = -1 }\\ { y = {(63 / x)} - 2 ^ {4} }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=-79$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{63}{-1}-2^{4}$$

Fraction \frac{63}{-1} can be rewritten as -63 by extracting the negative sign.

$$y=-63-2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$y=-63-16$$

Subtract 16 from -63 to get -79.

$$y=-79$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-79$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-79$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-79$$

The system is now solved.

$$x=-1 y=-79 z=-79 a=-79 b=-79$$