Solve {l}{x=-1}{y={(63/x)}-2^4}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = -1 }\\ { y = {(63 / x)} - 2 ^ {4} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-79$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{63}{-1}-2^{4}$$

Fraction \frac{63}{-1} can be rewritten as -63 by extracting the negative sign.

$$y=-63-2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$y=-63-16$$

Subtract 16 from -63 to get -79.

$$y=-79$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-79$$

The system is now solved.

$$x=-1 y=-79 z=-79$$