Solve {l}{x=(40)^2}{y=100*x+300}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = {(40)} ^ {2} }\\ { y = 100 \cdot x + 300 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=160300$$

Solution Steps

Consider the first equation. Calculate 40 to the power of 2 and get 1600.

$$x=1600$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=100\times 1600+300$$

Multiply 100 and 1600 to get 160000.

$$y=160000+300$$

Add 160000 and 300 to get 160300.

$$y=160300$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=160300$$

The system is now solved.

$$x=1600 y=160300 z=160300$$