Solve {l}{x={(-5)}-{(-38)}+{(-19)}+{(-2)}*18+{(-9)}}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = {(-5)} - {(-38)} + {(-19)} + {(-2)} \cdot 18 + {(-9)} }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-31$$

Solution Steps

Consider the first equation. The opposite of -38 is 38.

$$x=-5+38-19-2\times 18-9$$

Add -5 and 38 to get 33.

$$x=33-19-2\times 18-9$$

Subtract 19 from 33 to get 14.

$$x=14-2\times 18-9$$

Multiply -2 and 18 to get -36.

$$x=14-36-9$$

Subtract 36 from 14 to get -22.

$$x=-22-9$$

Subtract 9 from -22 to get -31.

$$x=-31$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-31$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-31$$

The system is now solved.

$$x=-31 y=-31 z=-31$$