Solve {l}{x=sqrt[3]{64}}{y=sqrt[3]{4*4*4}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = \sqrt[3]{64} }\\ { y = \sqrt[3]{4 \cdot 4 \cdot 4} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=4$$

Solution Steps

Consider the second equation. Multiply 4 and 4 to get 16.

$$y=\sqrt[3]{16\times 4}$$

Multiply 16 and 4 to get 64.

$$y=\sqrt[3]{64}$$

Calculate \sqrt[3]{64} and get 4.

$$y=4$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=4$$

The system is now solved.

$$x=\sqrt[3]{64} y=4 z=4$$