Solve for x, y, z, a
a = \frac{7}{3} = 2\frac{1}{3} \approx 2.333333333
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y=\frac{3}{2}
Consider the second equation. Reduce the fraction \frac{9}{6} to lowest terms by extracting and canceling out 3.
z=\frac{5}{6}+\frac{3}{2}
Consider the third equation. Insert the known values of variables into the equation.
z=\frac{7}{3}
Add \frac{5}{6} and \frac{3}{2} to get \frac{7}{3}.
a=\frac{7}{3}
Consider the fourth equation. Insert the known values of variables into the equation.
x=\frac{5}{6} y=\frac{3}{2} z=\frac{7}{3} a=\frac{7}{3}
The system is now solved.
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