Solve {l}{x=2x-1/2/1/2}{y=2x+2*2}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = \frac{2 x - 1}{2} / \frac{1}{2} }\\ { y = 2 x + 2 \cdot 2 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=6$$

Solution Steps

Consider the first equation. Divide each term of 2x-1 by 2 to get x-\frac{1}{2}.

$$x=\frac{x-\frac{1}{2}}{\frac{1}{2}}$$

Divide each term of x-\frac{1}{2} by \frac{1}{2} to get -1+2x.

$$x=-1+2x$$

Subtract 2x from both sides.

$$x-2x=-1$$

Combine x and -2x to get -x.

$$-x=-1$$

Divide both sides by -1.

$$x=\frac{-1}{-1}$$

Divide -1 by -1 to get 1.

$$x=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=2\times 1+2\times 2$$

Do the multiplications.

$$y=2+4$$

Add 2 and 4 to get 6.

$$y=6$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=6$$

The system is now solved.

$$x=1 y=6 z=6$$