Solve {l}{x=1/3+1/6+1/4+1/3}{y=3}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = \frac{1}{3} + \frac{1}{6} + \frac{1}{4} + \frac{1}{3} }\\ { y = 3 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=3$$

Solution Steps

Consider the first equation. Add \frac{1}{3} and \frac{1}{6} to get \frac{1}{2}.

$$x=\frac{1}{2}+\frac{1}{4}+\frac{1}{3}$$

Add \frac{1}{2} and \frac{1}{4} to get \frac{3}{4}.

$$x=\frac{3}{4}+\frac{1}{3}$$

Add \frac{3}{4} and \frac{1}{3} to get \frac{13}{12}.

$$x=\frac{13}{12}$$

The system is now solved.

$$x=\frac{13}{12} y=3 z=3$$