Solve {l}{x=1/2}{y={(frac{5*{(2)}+1}{2})}-4x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = \frac{1}{2} }\\ { y = {(\frac{5 \cdot {(2)} + 1}{2})} - 4 x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{7}{2} = 3\frac{1}{2} = 3.5$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{5\times 2+1}{2}-4\times \frac{1}{2}$$

Multiply 5 and 2 to get 10.

$$y=\frac{10+1}{2}-4\times \frac{1}{2}$$

Add 10 and 1 to get 11.

$$y=\frac{11}{2}-4\times \frac{1}{2}$$

Multiply -4 and \frac{1}{2} to get -2.

$$y=\frac{11}{2}-2$$

Subtract 2 from \frac{11}{2} to get \frac{7}{2}.

$$y=\frac{7}{2}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{7}{2}$$

The system is now solved.

$$x=\frac{1}{2} y=\frac{7}{2} z=\frac{7}{2}$$