Solve for x, y, z
z = \frac{128}{5} = 25\frac{3}{5} = 25.6
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5x=2\times 64
Consider the first equation. Multiply both sides of the equation by 40, the least common multiple of 8,20.
5x=128
Multiply 2 and 64 to get 128.
x=\frac{128}{5}
Divide both sides by 5.
y=\frac{128}{5}
Consider the second equation. Insert the known values of variables into the equation.
z=\frac{128}{5}
Consider the third equation. Insert the known values of variables into the equation.
x=\frac{128}{5} y=\frac{128}{5} z=\frac{128}{5}
The system is now solved.
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