Solve {l}{x+45=9}{y=x}{z=45+63}{text{Solvefor}a,btext{where}}{a=y}{b=z}

$$\left. \begin{array} { l } { x + 45 = 9 }\\ { y = x }\\ { z = 45 + 63 }\\ { \text{Solve for } a,b \text{ where} } \\ { a = y }\\ { b = z } \end{array} \right.$$

Solve for x, y, z, a, b

$$a=-36$$

$$b=108$$

Solution Steps

Consider the first equation. Subtract 45 from both sides.

$$x=9-45$$

Subtract 45 from 9 to get -36.

$$x=-36$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-36$$

Consider the third equation. Add 45 and 63 to get 108.

$$z=108$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-36$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=108$$

The system is now solved.

$$x=-36 y=-36 z=108 a=-36 b=108$$