Solve {l}{x+3x=15}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { x + 3 x = 15 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b = \frac{15}{4} = 3\frac{3}{4} = 3.75$$

Solution Steps

Consider the first equation. Combine x and 3x to get 4x.

$$4x=15$$

Divide both sides by 4.

$$x=\frac{15}{4}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{15}{4}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{15}{4}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=\frac{15}{4}$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=\frac{15}{4}$$

The system is now solved.

$$x=\frac{15}{4} y=\frac{15}{4} z=\frac{15}{4} a=\frac{15}{4} b=\frac{15}{4}$$