Solve for x, y, z, a
a=40
Share
Copied to clipboard
100x+18x=1700
Consider the first equation. Multiply both sides of the equation by 100.
118x=1700
Combine 100x and 18x to get 118x.
x=\frac{1700}{118}
Divide both sides by 118.
x=\frac{850}{59}
Reduce the fraction \frac{1700}{118} to lowest terms by extracting and canceling out 2.
x=\frac{850}{59} y=40 z=40 a=40
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}