Solve {l}{r=3}{s=9r+4r-3r*2-10}{text{Solvefor}ttext{where}}{t=s}

$$\left. \begin{array} { l } { r = 3 }\\ { s = 9 r + 4 r - 3 r \cdot 2 - 10 }\\ { \text{Solve for } t \text{ where} } \\ { t = s } \end{array} \right.$$

Solve for r, s, t

$$t=11$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$s=9\times 3+4\times 3-3\times 3\times 2-10$$

Do the multiplications.

$$s=27+12-3\times 3\times 2-10$$

Add 27 and 12 to get 39.

$$s=39-3\times 3\times 2-10$$

Multiply 3 and 3 to get 9.

$$s=39-9\times 2-10$$

Multiply 9 and 2 to get 18.

$$s=39-18-10$$

Subtract 18 from 39 to get 21.

$$s=21-10$$

Subtract 10 from 21 to get 11.

$$s=11$$

Consider the third equation. Insert the known values of variables into the equation.

$$t=11$$

The system is now solved.

$$r=3 s=11 t=11$$