Solve {l}{r=-2}{s={(3r/5)}^2}{text{Solvefor}ttext{where}}{t=s}

$$\left. \begin{array} { l } { r = -2 }\\ { s = {(\frac{3 r}{5})} ^ {2} }\\ { \text{Solve for } t \text{ where} } \\ { t = s } \end{array} \right.$$

Solve for r, s, t

$$t = \frac{36}{25} = 1\frac{11}{25} = 1.44$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$s=\left(\frac{3\left(-2\right)}{5}\right)^{2}$$

Multiply 3 and -2 to get -6.

$$s=\left(\frac{-6}{5}\right)^{2}$$

Fraction \frac{-6}{5} can be rewritten as -\frac{6}{5} by extracting the negative sign.

$$s=\left(-\frac{6}{5}\right)^{2}$$

Calculate -\frac{6}{5} to the power of 2 and get \frac{36}{25}.

$$s=\frac{36}{25}$$

Consider the third equation. Insert the known values of variables into the equation.

$$t=\frac{36}{25}$$

The system is now solved.

$$r=-2 s=\frac{36}{25} t=\frac{36}{25}$$