Solve {l}{r=sqrt{(0)^2+(0)^2-6^2}sqrt{36}}{s=14}{text{Solvefor}ttext{where}}{t=s}

$$\left. \begin{array} { l } { r = \sqrt{{(0)} ^ {2} + {(0)} ^ {2} - 6 ^ {2}} \sqrt{36} }\\ { s = 14 }\\ { \text{Solve for } t \text{ where} } \\ { t = s } \end{array} \right.$$

Solve for r, s, t

$$t=14$$

Solution Steps

Consider the first equation. Calculate 0 to the power of 2 and get 0.

$$r=\sqrt{0+0^{2}-6^{2}}\sqrt{36}$$

Calculate 0 to the power of 2 and get 0.

$$r=\sqrt{0+0-6^{2}}\sqrt{36}$$

Add 0 and 0 to get 0.

$$r=\sqrt{0-6^{2}}\sqrt{36}$$

Calculate 6 to the power of 2 and get 36.

$$r=\sqrt{0-36}\sqrt{36}$$

Subtract 36 from 0 to get -36.

$$r=\sqrt{-36}\sqrt{36}$$

Calculate the square root of -36 and get 6i.

$$r=6i\sqrt{36}$$

Calculate the square root of 36 and get 6.

$$r=6i\times 6$$

Multiply 6i and 6 to get 36i.

$$r=36i$$

The system is now solved.

$$r=36i s=14 t=14$$