Solve {l}{n=1}{o=(n+n+2)^-n+2}{text{Solvefor}ptext{where}}{p=o}

$$\left. \begin{array} { l } { n = 1 }\\ { o = {(n + n + 2)} ^ {-n + 2} }\\ { \text{Solve for } p \text{ where} } \\ { p = o } \end{array} \right.$$

Solve for n, o, p

$$p=4$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$o=\left(1+1+2\right)^{-1+2}$$

Add 1 and 1 to get 2.

$$o=\left(2+2\right)^{-1+2}$$

Add 2 and 2 to get 4.

$$o=4^{-1+2}$$

Add -1 and 2 to get 1.

$$o=4^{1}$$

Calculate 4 to the power of 1 and get 4.

$$o=4$$

Consider the third equation. Insert the known values of variables into the equation.

$$p=4$$

The system is now solved.

$$n=1 o=4 p=4$$