Solve {l}{m=7}{n=3{(2-3)}}{o=n}{p=o}{q=p}{r=q}{text{Solvefor}stext{where}}{s=r}

$$\left. \begin{array} { l } { m = 7 }\\ { n = 3 {(2 - 3)} }\\ { o = n }\\ { p = o }\\ { q = p }\\ { r = q }\\ { \text{Solve for } s \text{ where} } \\ { s = r } \end{array} \right.$$

Solve for m, n, o, p, q, r, s

$$s=-3$$

Solution Steps

Consider the second equation. Subtract 3 from 2 to get -1.

$$n=3\left(-1\right)$$

Multiply 3 and -1 to get -3.

$$n=-3$$

Consider the third equation. Insert the known values of variables into the equation.

$$o=-3$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$p=-3$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$q=-3$$

Consider the equation (6). Insert the known values of variables into the equation.

$$r=-3$$

Consider the equation (7). Insert the known values of variables into the equation.

$$s=-3$$

The system is now solved.

$$m=7 n=-3 o=-3 p=-3 q=-3 r=-3 s=-3$$