Solve {l}{m=1.2}{n=-1}{o={(-10m^2n^6)}*{(-20mn^15)}}{text{Solvefor}ptext{where}}{p=o}

$$\left. \begin{array} { l } { m = 1.2 }\\ { n = -1 }\\ { o = {(-10 m ^ {2} n ^ {6})} \cdot {(-20 m n ^ {15})} }\\ { \text{Solve for } p \text{ where} } \\ { p = o } \end{array} \right.$$

Solve for m, n, o, p

$$p=-345.6$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$o=-10\times 1.2^{2}\left(-1\right)^{6}\left(-20\right)\times 1.2\left(-1\right)^{15}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$o=-10\times 1.2^{3}\left(-1\right)^{6}\left(-20\right)\left(-1\right)^{15}$$

To multiply powers of the same base, add their exponents. Add 6 and 15 to get 21.

$$o=-10\times 1.2^{3}\left(-1\right)^{21}\left(-20\right)$$

Calculate 1.2 to the power of 3 and get 1.728.

$$o=-10\times 1.728\left(-1\right)^{21}\left(-20\right)$$

Multiply -10 and 1.728 to get -17.28.

$$o=-17.28\left(-1\right)^{21}\left(-20\right)$$

Calculate -1 to the power of 21 and get -1.

$$o=-17.28\left(-1\right)\left(-20\right)$$

Multiply -17.28 and -1 to get 17.28.

$$o=17.28\left(-20\right)$$

Multiply 17.28 and -20 to get -345.6.

$$o=-345.6$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$p=-345.6$$

The system is now solved.

$$m=1.2 n=-1 o=-345.6 p=-345.6$$