Solve for x
\left\{\begin{matrix}x=-\frac{l}{2\left(2y-1\right)}\text{, }&l\neq 0\text{ and }y\neq \frac{1}{2}\\x\neq 0\text{, }&y=\frac{1}{2}\text{ and }l=0\end{matrix}\right.
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l+4yx+x\left(-2\right)=0
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
4yx+x\left(-2\right)=-l
Subtract l from both sides. Anything subtracted from zero gives its negation.
\left(4y-2\right)x=-l
Combine all terms containing x.
\frac{\left(4y-2\right)x}{4y-2}=-\frac{l}{4y-2}
Divide both sides by 4y-2.
x=-\frac{l}{4y-2}
Dividing by 4y-2 undoes the multiplication by 4y-2.
x=-\frac{l}{2\left(2y-1\right)}
Divide -l by 4y-2.
x=-\frac{l}{2\left(2y-1\right)}\text{, }x\neq 0
Variable x cannot be equal to 0.
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