Solve {l}{i{(x)}=-0}{j=2x+3}{text{Solvefor}ktext{where}}{k=j}

$$\left. \begin{array} { l } { i {(x)} = -0 }\\ { j = 2 x + 3 }\\ { \text{Solve for } k \text{ where} } \\ { k = j } \end{array} \right.$$

Solve for x, j, k

$$k=3$$

Solution Steps

Consider the first equation. Divide both sides by i. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$j=2\times 0+3$$

Multiply 2 and 0 to get 0.

$$j=0+3$$

Add 0 and 3 to get 3.

$$j=3$$

Consider the third equation. Insert the known values of variables into the equation.

$$k=3$$

The system is now solved.

$$x=0 j=3 k=3$$