Solve {l}{f{(x)}=x^2+1}{x=2}{g=f{(x)}}{text{Solvefor}htext{where}}{h=g}

$$\left. \begin{array} { l } { f {(x)} = x ^ {2} + 1 }\\ { x = 2 }\\ { g = f {(x)} }\\ { \text{Solve for } h \text{ where} } \\ { h = g } \end{array} \right.$$

Solve for f, x, g, h

$$h=5$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$f\times 2=2^{2}+1$$

Calculate 2 to the power of 2 and get 4.

$$f\times 2=4+1$$

Add 4 and 1 to get 5.

$$f\times 2=5$$

Divide both sides by 2.

$$f=\frac{5}{2}$$

Consider the third equation. Insert the known values of variables into the equation.

$$g=\frac{5}{2}\times 2$$

Multiply \frac{5}{2} and 2 to get 5.

$$g=5$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$h=5$$

The system is now solved.

$$f=\frac{5}{2} x=2 g=5 h=5$$