Solve {l}{f{(x)}=2x^2+3}{x=5}{g=f{(x)}}{text{Solvefor}htext{where}}{h=g}

$$\left. \begin{array} { l } { f {(x)} = 2 x ^ {2} + 3 }\\ { x = 5 }\\ { g = f {(x)} }\\ { \text{Solve for } h \text{ where} } \\ { h = g } \end{array} \right.$$

Solve for f, x, g, h

$$h=53$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$f\times 5=2\times 5^{2}+3$$

Calculate 5 to the power of 2 and get 25.

$$f\times 5=2\times 25+3$$

Multiply 2 and 25 to get 50.

$$f\times 5=50+3$$

Add 50 and 3 to get 53.

$$f\times 5=53$$

Divide both sides by 5.

$$f=\frac{53}{5}$$

Consider the third equation. Insert the known values of variables into the equation.

$$g=\frac{53}{5}\times 5$$

Multiply \frac{53}{5} and 5 to get 53.

$$g=53$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$h=53$$

The system is now solved.

$$f=\frac{53}{5} x=5 g=53 h=53$$