Solve {l}{f{(1)}=1/2{(1)}-3}{g=1}{text{Solvefor}htext{where}}{h=g}

$$\left. \begin{array} { l } { f {(1)} = \frac{1}{2} {(1)} - 3 }\\ { g = 1 }\\ { \text{Solve for } h \text{ where} } \\ { h = g } \end{array} \right.$$

Solve for f, g, h

$$h=1$$

Solution Steps

Consider the first equation. Multiply \frac{1}{2} and 1 to get \frac{1}{2}.

$$f\times 1=\frac{1}{2}-3$$

Subtract 3 from \frac{1}{2} to get -\frac{5}{2}.

$$f\times 1=-\frac{5}{2}$$

Divide both sides by 1.

$$f=\frac{-\frac{5}{2}}{1}$$

Express \frac{-\frac{5}{2}}{1} as a single fraction.

$$f=\frac{-5}{2\times 1}$$

Multiply 2 and 1 to get 2.

$$f=\frac{-5}{2}$$

Fraction \frac{-5}{2} can be rewritten as -\frac{5}{2} by extracting the negative sign.

$$f=-\frac{5}{2}$$

The system is now solved.

$$f=-\frac{5}{2} g=1 h=1$$