Solve {l}{b=1}{c=8*{(frac{1*{(3)}+1}{3})}+sqrt[3]{-0*0*0*1}*9}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { b = 1 }\\ { c = 8 \cdot {(\frac{1 \cdot {(3)} + 1}{3})} + \sqrt[3]{-0 \cdot 0 \cdot 0 \cdot 1} \cdot 9 }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for b, c, d

$$d = \frac{32}{3} = 10\frac{2}{3} \approx 10.666666667$$

Solution Steps

Consider the second equation. Multiply 1 and 3 to get 3.

$$c=8\times \frac{3+1}{3}+\sqrt[3]{0\times 0\times 0\times 1}\times 9$$

Add 3 and 1 to get 4.

$$c=8\times \frac{4}{3}+\sqrt[3]{0\times 0\times 0\times 1}\times 9$$

Multiply 8 and \frac{4}{3} to get \frac{32}{3}.

$$c=\frac{32}{3}+\sqrt[3]{0\times 0\times 0\times 1}\times 9$$

Multiply 0 and 0 to get 0.

$$c=\frac{32}{3}+\sqrt[3]{0\times 0\times 1}\times 9$$

Multiply 0 and 0 to get 0.

$$c=\frac{32}{3}+\sqrt[3]{0\times 1}\times 9$$

Multiply 0 and 1 to get 0.

$$c=\frac{32}{3}+\sqrt[3]{0}\times 9$$

Calculate \sqrt[3]{0} and get 0.

$$c=\frac{32}{3}+0\times 9$$

Multiply 0 and 9 to get 0.

$$c=\frac{32}{3}+0$$

Add \frac{32}{3} and 0 to get \frac{32}{3}.

$$c=\frac{32}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$d=\frac{32}{3}$$

The system is now solved.

$$b=1 c=\frac{32}{3} d=\frac{32}{3}$$