Solve for a_n, n, a, b
b=2
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a_{n}=4\times 3^{1-1}
Consider the first equation. Insert the known values of variables into the equation.
a_{n}=4\times 3^{0}
Subtract 1 from 1 to get 0.
a_{n}=4\times 1
Calculate 3 to the power of 0 and get 1.
a_{n}=4
Multiply 4 and 1 to get 4.
a_{n}=4 n=1 a=2 b=2
The system is now solved.
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