Solve {l}{a=5}{b=7}{a+b=x}{y=2x*8}{z=24*8}{text{Solvefor}c,dtext{where}}{c=y}{d=z}

$$\left. \begin{array} { l } { a = 5 }\\ { b = 7 }\\ { a + b = x }\\ { y = 2 x \cdot 8 }\\ { z = 24 \cdot 8 }\\ { \text{Solve for } c,d \text{ where} } \\ { c = y }\\ { d = z } \end{array} \right.$$

Solve for a, b, x, y, z, c, d

$$c=192$$

$$d=192$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$5+7=x$$

Add 5 and 7 to get 12.

$$12=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=12$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$y=2\times 12\times 8$$

Multiply 2 and 12 to get 24.

$$y=24\times 8$$

Multiply 24 and 8 to get 192.

$$y=192$$

Consider the fifth equation. Multiply 24 and 8 to get 192.

$$z=192$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=192$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=192$$

The system is now solved.

$$a=5 b=7 x=12 y=192 z=192 c=192 d=192$$