Solve {l}{a=3}{b=2}{c=sqrt[3]{a^2+b}}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { a = 3 }\\ { b = 2 }\\ { c = \sqrt[3]{a ^ {2} + b} }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for a, b, c, d

$$d=\sqrt[3]{11}\approx 2.223980091$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$c=\sqrt[3]{3^{2}+2}$$

Calculate 3 to the power of 2 and get 9.

$$c=\sqrt[3]{9+2}$$

Add 9 and 2 to get 11.

$$c=\sqrt[3]{11}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$d=\sqrt[3]{11}$$

The system is now solved.

$$a=3 b=2 c=\sqrt[3]{11} d=\sqrt[3]{11}$$