Solve {l}{a=-8}{a^2-11n+24=0}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { a = -8 }\\ { a ^ {2} - 11 n + 24 = 0 }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for a, n, b, c

$$c=-8$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$\left(-8\right)^{2}-11n+24=0$$

Calculate -8 to the power of 2 and get 64.

$$64-11n+24=0$$

Add 64 and 24 to get 88.

$$88-11n=0$$

Subtract 88 from both sides. Anything subtracted from zero gives its negation.

$$-11n=-88$$

Divide both sides by -11.

$$n=\frac{-88}{-11}$$

Divide -88 by -11 to get 8.

$$n=8$$

The system is now solved.

$$a=-8 n=8 b=-8 c=-8$$