Solve {l}{a=-3}{b=-2}{c={(2a-ab)}b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { a = -3 }\\ { b = -2 }\\ { c = {(2 a - a b)} b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for a, b, c, d

$$d=24$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$c=\left(2\left(-3\right)-\left(-3\left(-2\right)\right)\right)\left(-2\right)$$

Do the multiplications.

$$c=\left(-6+3\left(-2\right)\right)\left(-2\right)$$

Multiply 3 and -2 to get -6.

$$c=\left(-6-6\right)\left(-2\right)$$

Subtract 6 from -6 to get -12.

$$c=-12\left(-2\right)$$

Multiply -12 and -2 to get 24.

$$c=24$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$d=24$$

The system is now solved.

$$a=-3 b=-2 c=24 d=24$$