Solve {l}{M=8^3+9^2}{a=M^-1}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { M = 8 ^ {3} + 9 ^ {2} }\\ { a = M ^ {-1} }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for M, a, b

$$b=\frac{1}{593}\approx 0.001686341$$

Solution Steps

Consider the first equation. Calculate 8 to the power of 3 and get 512.

$$M=512+9^{2}$$

Calculate 9 to the power of 2 and get 81.

$$M=512+81$$

Add 512 and 81 to get 593.

$$M=593$$

Consider the second equation. Insert the known values of variables into the equation.

$$a=593^{-1}$$

Calculate 593 to the power of -1 and get \frac{1}{593}.

$$a=\frac{1}{593}$$

Consider the third equation. Insert the known values of variables into the equation.

$$b=\frac{1}{593}$$

The system is now solved.

$$M=593 a=\frac{1}{593} b=\frac{1}{593}$$