Solve {l}{B={({(-10)}{(2)}-{(8)}{(-5)})}}{a={(12/6*3-28-{(15*2)})}}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { B = {({(-10)} {(2)} - {(8)} {(-5)})} }\\ { a = {(\frac{12}{6} \cdot 3 - 28 - {(15 \cdot 2)})} }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for B, a, b

$$b=-52$$

Solution Steps

Consider the first equation. Multiply -10 and 2 to get -20.

$$B=-20-8\left(-5\right)$$

Multiply 8 and -5 to get -40.

$$B=-20-\left(-40\right)$$

The opposite of -40 is 40.

$$B=-20+40$$

Add -20 and 40 to get 20.

$$B=20$$

Consider the second equation. Divide 12 by 6 to get 2.

$$a=2\times 3-28-15\times 2$$

Multiply 2 and 3 to get 6.

$$a=6-28-15\times 2$$

Subtract 28 from 6 to get -22.

$$a=-22-15\times 2$$

Multiply 15 and 2 to get 30.

$$a=-22-30$$

Subtract 30 from -22 to get -52.

$$a=-52$$

Consider the third equation. Insert the known values of variables into the equation.

$$b=-52$$

The system is now solved.

$$B=20 a=-52 b=-52$$