Solve {l}{A=6/59|-2|89}{a=|A|}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { A = \frac{6}{5} 9 | -2 | 89 }\\ { a = | A | }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for A, a, b

$$b = \frac{9612}{5} = 1922\frac{2}{5} = 1922.4$$

Solution Steps

Consider the first equation. Multiply \frac{6}{5} and 9 to get \frac{54}{5}.

$$A=\frac{54}{5}|-2|\times 89$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.

$$A=\frac{54}{5}\times 2\times 89$$

Multiply \frac{54}{5} and 2 to get \frac{108}{5}.

$$A=\frac{108}{5}\times 89$$

Multiply \frac{108}{5} and 89 to get \frac{9612}{5}.

$$A=\frac{9612}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$a=|\frac{9612}{5}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{9612}{5} is \frac{9612}{5}.

$$a=\frac{9612}{5}$$

Consider the third equation. Insert the known values of variables into the equation.

$$b=\frac{9612}{5}$$

The system is now solved.

$$A=\frac{9612}{5} a=\frac{9612}{5} b=\frac{9612}{5}$$