Solve {l}{98x=164.91}{y=15.95+0}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 98 x = 164.91 }\\ { y = 15.95 + 0 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=15.95$$

Solution Steps

Consider the first equation. Divide both sides by 98.

$$x=\frac{164.91}{98}$$

Expand \frac{164.91}{98} by multiplying both numerator and the denominator by 100.

$$x=\frac{16491}{9800}$$

Consider the second equation. Add 15.95 and 0 to get 15.95.

$$y=15.95$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=15.95$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=15.95$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=15.95$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=15.95$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=15.95$$

The system is now solved.

$$x=\frac{16491}{9800} y=15.95 z=15.95 a=15.95 b=15.95 c=15.95 d=15.95$$