Solve {l}{9+2b=5}{c=9-3b-2}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 9 + 2 b = 5 }\\ { c = 9 - 3 b - 2 }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for b, c, d

$$d=13$$

Solution Steps

Consider the first equation. Subtract 9 from both sides.

$$2b=5-9$$

Subtract 9 from 5 to get -4.

$$2b=-4$$

Divide both sides by 2.

$$b=\frac{-4}{2}$$

Divide -4 by 2 to get -2.

$$b=-2$$

Consider the second equation. Insert the known values of variables into the equation.

$$c=9-3\left(-2\right)-2$$

Multiply -3 and -2 to get 6.

$$c=9+6-2$$

Add 9 and 6 to get 15.

$$c=15-2$$

Subtract 2 from 15 to get 13.

$$c=13$$

Consider the third equation. Insert the known values of variables into the equation.

$$d=13$$

The system is now solved.

$$b=-2 c=13 d=13$$