Solve {l}{74*0.74=a}{56*0.088+34.89=b}{c=a-b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 74 \cdot 0.74 = a }\\ { 56 \cdot 0.088 + 34.89 = b }\\ { c = a - b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for a, b, c, d

$$d=14.942$$

Solution Steps

Consider the first equation. Multiply 74 and 0.74 to get 54.76.

$$54.76=a$$

Swap sides so that all variable terms are on the left hand side.

$$a=54.76$$

Consider the second equation. Multiply 56 and 0.088 to get 4.928.

$$4.928+34.89=b$$

Add 4.928 and 34.89 to get 39.818.

$$39.818=b$$

Swap sides so that all variable terms are on the left hand side.

$$b=39.818$$

Consider the third equation. Insert the known values of variables into the equation.

$$c=54.76-39.818$$

Subtract 39.818 from 54.76 to get 14.942.

$$c=14.942$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$d=14.942$$

The system is now solved.

$$a=54.76 b=39.818 c=14.942 d=14.942$$