Solve {l}{729+45x=12}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 729 + 45 x = 12 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = -\frac{239}{15} = -15\frac{14}{15} \approx -15.933333333$$

Solution Steps

Consider the first equation. Subtract 729 from both sides.

$$45x=12-729$$

Subtract 729 from 12 to get -717.

$$45x=-717$$

Divide both sides by 45.

$$x=\frac{-717}{45}$$

Reduce the fraction \frac{-717}{45} to lowest terms by extracting and canceling out 3.

$$x=-\frac{239}{15}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-\frac{239}{15}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-\frac{239}{15}$$

The system is now solved.

$$x=-\frac{239}{15} y=-\frac{239}{15} z=-\frac{239}{15}$$