Solve {l}{7*x+5=-4/9}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 7 \cdot x + 5 = -\frac{4}{9} }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Subtract 5 from both sides.

$$7x=-\frac{4}{9}-5$$

Subtract 5 from -\frac{4}{9} to get -\frac{49}{9}.

$$7x=-\frac{49}{9}$$

Divide both sides by 7.

$$x=\frac{-\frac{49}{9}}{7}$$

Express \frac{-\frac{49}{9}}{7} as a single fraction.

$$x=\frac{-49}{9\times 7}$$

Multiply 9 and 7 to get 63.

$$x=\frac{-49}{63}$$

Reduce the fraction \frac{-49}{63} to lowest terms by extracting and canceling out 7.

$$x=-\frac{7}{9}$$

The system is now solved.

$$x=-\frac{7}{9} y=0 z=0$$